Ergh... Hate to say this, but don't you have that 10 bits to the byte thing approximately ass-backwards? 10 bits for each byte (assuming 128kbit source material) = 160kbit, = 20kbytes, not 12.8kbytes Your numbers seem to be assuming either further compression on the stream, or negative overheads (*1) Cheers -N *1 - If you have in fact cracked the holy grail of negative overheading, please let me know. I'll give you beer. On 16/04/07, Richard Naylor <richard.naylor(a)r2.co.nz> wrote:
At 02:49 p.m. 16/04/2007 +1200, Neil Gardner wrote:
Dammit - I know we've been asked to stop this, but now something interesting has happened...
you found the beer ?
Richard, you, who I know has great experience in this, have posted figures that are UNDER my very basic but probably right theoretical minimums
How do you fit 3600 seconds at 128kbps into 46MB ? I get 56.25MB...
I have this ancient spreadsheet with a few assumptions....
I basically round 10bits to the byte to cover overheads in the packet, etc.
So a data rate of say 128kbps is 12.8KB per sec or 0.13Mbps 768KB per minute or 7.68Mbps 46080 KB per hour or 460.9 Mbps or 46.08